8x=2x^2-4x

Solution for 8x=2x^2-4x equation:

8x=2x^2-4x

We move all terms to the left:

8x-(2x^2-4x)=0

We get rid of parentheses

-2x^2+8x+4x=0

We add all the numbers together, and all the variables

-2x^2+12x=0

a = -2; b = 12; c = 0;
Δ = b2-4ac
Δ = 122-4·(-2)·0
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{144}=12$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-12}{2*-2}=\frac{-24}{-4}
=+6
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+12}{2*-2}=\frac{0}{-4}
=0
$